What is the electric potential at the point indicated with the dot in the figure? Express your answer to two significant figures and include the appropriate units. 1.0 nC 3.0 cm, 3.0 cm 3.0 cm -2.0 nC -2.0 ncSEE THE ANSWER!
75 V 50 V 25 V OV cm 1 cm Part A Determine the magnitude and direction of the electric field at point 1 in the figure E1=(2500V/m,up) E1+=(7500V/m,up) E1-→=(3750V/m, down) E1—-=(2500V/m, down) Part B Determine the magnitude and direction of the electric field at point 2 in the figure. E2-=(2500V/m,up) E2—-=(3750V/m, down) E2–=(7500V/m.down) E2-=(5000V/m,up)SEE THE ANSWER!
Anna holds a 11 D magnifier directly in front of her eye to get a close look at a 19-mm -diameter penny. Assume a typical 25 cm near point and a distance of 1.7 cm between the lens and the retina. Part A: What is the closest possible distance that she can hold the coin to have it appear in focus? Express your answer with the appropriate units. Answer: 6.7 cm Part B: At this distance, how large does the image of the coin appear on her retina? Express your answer with the appropriate units.SEE THE ANSWER!
For the following reaction: 1) Add curved arrows for the first step. 2) Draw both the organic and inorganic intermediate species. Include nonbonding electrons and charges, where applicable. Add a curved arrow to show how the final product is formed. HD CH Hic H B Hči: -CHESEE THE ANSWER!
A. An object is 1.0 cm tall and its erect image is 4.0 cm tall. What is the exact magnification? B. When using the Lens Equation, a virtual image has a a. positive object distance b. negative image distance C. The scale at the bottom of the diagram is calibrated in cm. Find the focal length of the lens (in cm). (Do not include units with the answer.) image object 20 10 30 40 50 60 uluSEE THE ANSWER!