Question:

show that f'(x) = 2/4x-x^2 when g(f(x)) = x-2 and g'(x) = 2

Last updated: 8/7/2022

show that f'(x) = 2/4x-x^2 when g(f(x)) = x-2 and g'(x) = 2

show that f'(x) = 2/4x-x^2 when g(f(x)) = x-2 and g'(x) = 2 -[f(x)]^2

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