Question:
238U decays in 14 steps that together constitute the net
Last updated: 6/12/2023
238U decays in 14 steps that together constitute the net reaction 238 U 206 Pb 60 8 He The sign represents some unknown particle particles Take 1 amu 931 5 MeV C The atomic masses of 238U 206Pb 4He are 238 050783u 205 974449u and 4 002603u respectively The Q value of the reaction is O 2 6 MeV O 4 4 MeV O 51 7 MeV 8 9 MeV k