Question:

A 54 35 pm In diamond carbon atom occupy FCC lattice points

Last updated: 7/4/2023

A 54 35 pm In diamond carbon atom occupy FCC lattice points

A 54 35 pm In diamond carbon atom occupy FCC lattice points as well as alternate tetrahedral voids If edge length of the unit cell is 356 pm then radius of carbon atom is A 77 07 pm B 154 14 pm C 251 7 pm D 89 pm