A dentist's drill starts from rest. After 3.10 s of constant angular acceleration it turns at a rate of 2.00 x 10* rev/min

Question

A dentist's drill starts from rest. After 3.10 s of constant angular acceleration it turns at a rate of 2.00 x 10* rev/min,
(a) Find the drill's angular acceleration.
rad/s2
(b) Determine the angle (in radians) through which the drill rotates during this period.
rad

Kunduz · Accepted Answer

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