Question:

Given: H₂(g) + Br₂(1)→ 2 HBr(g) ΔHx= -72.8 kJ Calculate the

Last updated: 8/9/2022

Given: H₂(g) + Br₂(1)→ 2 HBr(g) ΔHx= -72.8 kJ Calculate the

Given: H₂(g) + Br₂(1)→ 2 HBr(g) ΔHx= -72.8 kJ Calculate the amount of energy absorbed or released when 15.0 g of HBr(g) is formed. 4.85 kJ absorbed 6.75 kJ released 13.5 kJ released 607 kJ absorbed