Question:
Given the differential equation dy/dx = 2x^2+5/3y^2, find
Last updated: 7/20/2022
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Given the differential equation dy/dx = 2x^2+5/3y^2, find the particular solution, y = f(x), with the initial condition f(-3) = -2.
Last updated: 7/20/2022
Given the differential equation dy/dx = 2x^2+5/3y^2, find the particular solution, y = f(x), with the initial condition f(-3) = -2.