Given the following two reactions: (1)Ba(s) + Cl₂(g) →BaCl₂(s) AH(1) = -858.6 kJ (2)Mg(s) + Cl₂(g) →→→MgCl₂(s) AH(2) = -641.3 kJ

Question

Given the following two reactions:
(1)Ba(s) + Cl₂(g) →BaCl₂(s)
AH(1) = -858.6 kJ
(2)Mg(s) + Cl₂(g) →→→MgCl₂(s)
AH(2) = -641.3 kJ
calculate the enthalpy change for the following reaction:
(3) BaCl₂(s) + Mg(s) Ba(s) + MgCl₂(s)
AH(3) =
kJ

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