Moles of solute Molarity 120 60 moles of solute volume L of
Last updated: 7/3/2023
Moles of solute Molarity 120 60 moles of solute volume L of solution 2 05 mol L 2 mol 2 The mass of potassium dichromate crystals required to oxidise 750 cm of 06 M Mohr s salt solution is molar mass 392 a 0 49 g b 0 45 g c 22 05 g d 2 2 g Exp c Mohr s salt is FeSO NH SO 6H O Only oxidisable part Fe is Fe Fe e x6 00 14H 6e20 7H0 6Fe 0 0 14H Millimoles of Fe 750x0 6 450 Moles of Fe 450 1000 6 mol Fe 1 mol Cro 0450 mol Fe a 5 55x 10 M c 3 33x 10 M Exp a Molality 0 450 6 0 075 x 294 g 22 05 g 3 The molality of a urea solution in which 0 0100 g of urea NH CO is added to 0 3000 dm of water at STP is AIEEE 2011 W Molality Moles of urea 2 mol 0 974 L 300 ml x 6Fe 2Cr 7H O 0 0100 60 x 0 2999 0 450 mol moles of the solute mass of the solvent in kg 0 0100 g 19 mL AIEEE 2011 b 33 3M d 0 555 M 60 g mol Mass of 1000 mL of solution volume x density 0 075 mol Cr O 300 g Mass of solvent 300g 0 0100 g 299 9g 0 2999 kg t 1 dm 1000 mL 555 x 10 mol kg 4 Amount of oxalic acid present in a solution can be determined by its titration with KMnO solution in the presence of H SO The titration gives unsatisfactory result when carried out in the presence a gets oxidised by oxalic b furnishes H ions in addition to those from oxalic acid c reduces permanganate to Mn d oxidises oxalic acid to carbon dioxide and water Exp c Titration of oxalic acid by KMnO in the presence of HCI gives unsatisfactory result because HCI is a better reducing agent than oxalic acid and HCI reduces preferably MnO to Mn 45 In the reaction 2Al s 6HCl aq 2Al aq 6CI aq 3H g AIEEE 2007 a 6L HCl aq is consumed for every 3L H g produced b 33 6 LH g is produced regardless of temperature and pressure for every mole Al that reacts c 67 2 LH g at STP is produced for every mole Al that reacts d 11 2 LH g at STP is produced for every mole HCI aq consumed Exp d 2Al s 6HCl aq 2A aq 6C aq 3H g From the equation it is clear that 6 mol of HCI produces 3 mol of H 3 x 22 4 6 or 1 mole of HCI Lot H 11 2 L of H How many moles of magnesium phosphate Mg PO will contain 0 25 mole of oxygen atoms AIEEE 2006 a 0 02 c 1 25x 102 b 3 125 x 10 d 2 5x 10 Exp b 8 moles of O atom are contained by 1 mole Mg3 PO4 2 Hence 0 25 moles of O atom are contained by x 0 25 mol Mg PO4 3 125 x 10 8 47 If we consider that 1 6 in place of 1 12 mass of carbon atom is taken to be the relative atomic mass unit the mass of one mole of a substance will AIEEE 2005 a be a function of the molecular mass of the substance b remain unchanged c increase two fold d decrease twice Exp b The mass of one mole of a substance will remain unchanged