Given event T1, T2, T3, and D with p(D)=0.05,

Last updated: 7/19/2022

Given event T1, T2, T3, and D with p(D)=0.05, p(T1|D)=p(~T1|~D)=0.9, p(T2|D)=p(~T2|~D)=0.8, p(T3|D)=0.9 and p(~T3|~D)=1, find p(T1u T2uT3) if p(T∩T2)=0.05, p(T∩T3)=0.01, and T2 and T3 are mutually exclusive.