2Cr³+ + 3Cu²+ + 7H₂O --- 3Cu + Cr₂O72- + 14H+ In the above redox reaction, use oxidation numbers to identify the element

Question

2Cr³+ + 3Cu²+ + 7H₂O ---> 3Cu + Cr₂O72- + 14H+
In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing
agent and the reducing agent.
name of the element
oxidized:
formula of the oxidizing
agent:
name of the element
reduced:
formula of the reducing
agent:

Kunduz · Accepted Answer

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2Cr³+ + 3Cu²+ + 7H₂O ---> 3Cu + Cr₂O72- + 14H+ In the above