3 a 5 0 Given that the eigenvalue 3 is defective and the

Last updated: 5/9/2023

3 a 5 0 Given that the eigenvalue 3 is defective and the eigenvalue 5 is complete then a possible Jordan normal form of A is 310 0 03 0 0 00 0 0 0 5 30 0 03 0 0 00 50 0 0 0 5 31 0 0 03 1 0 00 5 1 000 5 10 0 0310 0 0 3 0 000 5 31 0 0 0300 00 50 0 5