Question:

A 52.0-mL volume of 0.35 M CH3COOH (K₁ = 1.8 x 10-5) is

Last updated: 8/5/2022

A 52.0-mL volume of 0.35 M CH3COOH (K₁ = 1.8 x 10-5) is

A 52.0-mL volume of 0.35 M CH3COOH (K₁ = 1.8 x 10-5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 23.0 mL of NaOH. Express your answer numerically.