Question:

A 55.1 mL sample of a 0.102 M potassium sulfate solution is

Last updated: 7/31/2022

A 55.1 mL sample of a 0.102 M potassium sulfate solution is

A 55.1 mL sample of a 0.102 M potassium sulfate solution is mixed with 39.0 mL of a 0.112 M lead (II) acetate solution and this precipitation reaction occurs: K₂SO4 (aq) + Pb(C₂H302)2 (aq) 2 KC 2H3O2 (aq) + PbSO4 (s) The solid PbSO4 (molar mass = 303.26 g/mol) is collected, dried, and found to have a mass of 1.04 g. Determine the theoretical yield in grams. (Answer to 2 decimal places)