Question:

A certain vehicle can accelerate from a standing start to a speed of v(t) = -0.27t² + 12t feet per second after t seconds (for 0 ≤ t < 30). (a) Find a formula for the distance that it will travel from its starting point in the first t seconds. [Hint: Integ

Last updated: 7/8/2022

A certain vehicle can accelerate from a standing start to a speed of v(t) = -0.27t² + 12t feet per second after t seconds (for
0 ≤ t < 30).
(a)
Find a formula for the distance that it will travel from its starting point in the first t seconds. [Hint: Integ

A certain vehicle can accelerate from a standing start to a speed of v(t) = -0.27t² + 12t feet per second after t seconds (for 0 ≤ t < 30). (a) Find a formula for the distance that it will travel from its starting point in the first t seconds. [Hint: Integrate velocity to find distance, and then use the fact that distance is 0 at time t = 0.] D(t) = (b) Use the formula that you found in part (a) to find the distance (in ft) that the car will travel in the first 10 seconds. (Round your answer to the nearest whole number.) D(10) = ft