a Find the class width Recall that the class width is computed by finding the difference of the largest data value and the

Question

a Find the class width Recall that the class width is computed by finding the difference of the largest data value and the smallest data value and dividing that difference by the desired number of classes Here we are asked to use five classes Therefore we have the following class width Now examine the data set and determine the largest and smallest data values Percent Male Students Enrolled in Coed Universities and Colleges 33 41 51 49 42 51 55 45 47 28 41 81 47 52 38 47 47 51 41 50 56 52 45 44 40 33 51 43 44 60 40 57 47 69 V The largest data value is 81 largest data value smallest data value desired number of classes 48 55 51 48 47 48 51 46 55 35 54 65 39 43 53 46 Step 3 largest data value smallest data value 7 5 X Step 2 Substitute the largest data value 81 and the smallest data value 28 into the formula for finding the class width for five classes and simplify the result largest data value class width 10 6 81 28 First class Third class 5 Second class The result is not an integer but it is illogical to talk about a fraction of a student Here to ensure the classes cover all the data we should round this value up to the next whole number Doing this allows us to state that the class width is 11 11 Fourth class b Make a frequency table showing class limits class boundaries midpoints frequencies relative frequencies and cumulative frequencies 5 Recall that a frequency table partitions data into classes or intervals of equal width The process of creating a frequency table has many steps First we will create the five distinct classes Determine all lower and upper class limits knowing that the smallest value is 28 the largest value is 81 and the class width is 11 39 ng 81 and the smallest data value is 28 smallest data value 28 10 6 50 61 Lower class limit Upper class limit 28 38 60

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