A sample of 28 weekly donntimes (in hours) for a computer produced a variance of 4.488. The null hypothesis is that the variance

Question

A sample of 28 weekly donntimes (in hours) for a computer produced a variance of 4.488. The null
hypothesis is that the variance of all dann-times for this type computer is equal to 5.
Assume that the population is normally distributed and significance level is 5% Then, the value of
chi-square Test statistic and the values of critical values of chi-square are respectively:
a) (24.235) and (14.573 and 43.195)
b) (17.602) and (13.844 and 41.923)
c) (28.193) and (15.308 and 44.461)
d) (31.784) and (12.879 and 40.113)

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