Question:

A student was asked to find a 99 confidence interval for the

Last updated: 4/22/2023

A student was asked to find a 99 confidence interval for the

A student was asked to find a 99 confidence interval for the proportion of students who take notes using data from a random sample of size n 81 Which of the following is a correct interpretation of the interval 0 1 p 0 29 Check all that are correct There is a 99 chance that the proportion of notetakers in a sample of 81 students will be between 0 1 and 0 29 The proportion of all students who take notes is between 0 1 and 0 29 99 of the time With 99 confidence a randomly selected student takes notes in a proportion of their classes that is between 0 1 and 0 29 There is a 99 chance that the proportion of the population is between 0 1 and 0 29 With 99 confidence the proportion of all students who take notes is between 0 1 and 0 38