Ammonia will react with fluorine to produce dinitrogen

Last updated: 7/30/2022

Ammonia will react with fluorine to produce dinitrogen tetrafluoride and hydrogen fluoride as follows: 2NH 3(g) + 5F 2(g) → N ₂F 4( g) + 6HF( g) How many moles of NH 3 are needed to react completely with 13.6 mol of F ₂? 27.2 mol 34.0 mol 5.44 mol 2.27 mol 6.80 mol