At 300 K and 1 atm 15 mL of a gaseous hydrocarbon requires

Last updated: 6/30/2023

At 300 K and 1 atm 15 mL of a gaseous hydrocarbon requires 375 mL air containing 20 O by volume for complete combustion After combustion the gases occupy 330 mL Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure the formula of the hydrocarbon is Main 2016 Offline 4 C H10 1 C H 2 C H JEE 3 C Hg