ativist formula the velocity comes out to be 0 999 c 21 a A

Last updated: 6/24/2023

ativist formula the velocity comes out to be 0 999 c 21 a A monoenergetic electron beam with electron speed of 5 20 x 106 m s is subject to a magnetic field of 1 30 x 104 T normal to the beam velocity What is the radius of the circle traced by the beam given e m for electron equals 1 76 x 10 1 C kg b Is the formula you employ in a valid for calculating radius of the path of a 20 MeV electron beam If not in what way is it modified Note Exercises 11 20 b and 11 21 b take you to relativistic mechanics which is beyond the scope of this book They have been inserted here simply to emphasise the point that the formulas you use in part a of the exercises are not valid at very high speeds or energies See answers at the end to know what very high speed or energy means Mv