Consider h(t) = t^3 + 3t² - 9t-3 on [-5, -2]. Determine the

Last updated: 7/5/2022

Consider h(t) = t^3 + 3t² - 9t-3 on [-5, -2]. Determine the interval over which h is continuous and the interval over which h is differentiable. h is continuous on h is differentiable on