Question:

Consider the curve parameterized by: x =2t^3/2 - 1 and y =

Last updated: 8/10/2022

Consider the curve parameterized by: x =2t^3/2 - 1 and y =

Consider the curve parameterized by: x =2t^3/2 - 1 and y = 5t. (a.) Find an equation for the line tangent to the curve at t = 1.