Example 2 Boron naturally occurs as a mixtu of boron 10 5

Last updated: 6/25/2023

Example 2 Boron naturally occurs as a mixtu of boron 10 5 protons 5 neutrons an boron 11 5 protons 6 neutrons isotope The percentage abundance of B 10 is 20 an that of B 11 is 80 Then the atomic mass boron is calculated as follows