Given that 4 NH3 + 5 O2 → 4 N+ 6 H₂O, if 3.00 mol NH3 were

Last updated: 7/27/2022

Given that 4 NH3 + 5 O2 → 4 N+ 6 H₂O, if 3.00 mol NH3 were made to react with excess of oxygen gas, the amount of H2formed would be: 3.5 moles 5.4 moles 4.5 moles 6.00 moles 2.5 moles