Question:

Given the equation 4y²u𝓏𝓏 + 2(1-y²)u𝓏ᵧ - uᵧᵧ- 2y(2uₓ -

Last updated: 8/6/2022

Given the equation 4y²u𝓏𝓏 + 2(1-y²)u𝓏ᵧ - uᵧᵧ- 2y(2uₓ -

Given the equation 4y²u𝓏𝓏 + 2(1-y²)u𝓏ᵧ - uᵧᵧ- 2y(2uₓ - uᵧ)/(1+ y²) = 0. Find the solution u(x, y) which satisfies u(x,0) = g(x) and uᵧ(x,0) = f(x), where f, g ∈ C²(R) are arbitrary functions.