Given the function g(x) = 6x³ + 45x² + 72x, find the first

Last updated: 8/14/2022

Given the function g(x) = 6x³ + 45x² + 72x, find the first derivative, g'(x) = 0 when a = 4, that is, g'(-4) = 0. Now, we want to know whether there is a local minimum or local maximum at z = 4, so we will use the second derivative test. Find the second derivative, g''(x). g''(x) = Evaluate g''(-4). g''(-4)= Based on the sign of this number, does this mean the graph of g(x) is concave up or concave down at a = - 4? At = - 4 the graph of g(x) is concave Based on the concavity of g(x) at x = At z = - 4 there is a local