Question:

Given z₁ = 24(cos 315° + isin 315°) and z2 = 3(cos 120

Last updated: 7/24/2022

Given z₁ = 24(cos 315° + isin 315°) and z2 = 3(cos 120

Given z₁ = 24(cos 315° + isin 315°) and z2 = 3(cos 120° + isin 120°), what is the product of z₁ and z₂?