Question:
How many moles of AI(NO3)3 are produced when 39.61 grams of
Last updated: 7/24/2022
How many moles of AI(NO3)3 are produced when 39.61 grams of HNO3 are reacted with excess Al(OH)3? Round your answer to three digits after the decimal point. Al(OH)3 + 3 HNO3 → AI(NO3)3 + 3 H₂O