If a ball is thrown straight up into the air with an initial velocity of 45 ft/s, its height in feet after t seconds is given by

Question

If a ball is thrown straight up into the air with an initial velocity of 45 ft/s, its height in feet after t seconds is given by y = 45t - 16t². Find the average velocity for the time period begining when t = 1 and lasting
(i) 0.1 seconds
(ii) 0.01 seconds
(iii) 0.001 seconds
Finally based on the above results, guess what the instantaneous velocity of the ball is when t = 1.

Kunduz · Accepted Answer

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