If the lines 3x² +8xy-3y² = 0 and 3x² +8xy-3y² +2x-4y-1=0

Last updated: 7/16/2022

If the lines 3x² +8xy-3y² = 0 and 3x² +8xy-3y² +2x-4y-1=0 from a quadrilateral ABCD. Then which of the following is/are true? The quadrilateral is a square One of the diagonal of the quadrilateral has equation 2x-4y-1=0 One of the vertex of the quadrilateral can be 3/10, -1/10 One of the side of quadrilateral has the equation as 3x-y-1=0