Question:

In a beaker, 0.86 mol of potassium iodide and 0.52 mol of

Last updated: 8/4/2022

In a beaker, 0.86 mol of potassium iodide and 0.52 mol of

In a beaker, 0.86 mol of potassium iodide and 0.52 mol of lead (II) nitrate are dissolved in water. A reaction occurs, and a white precipitate is observed. Calculate the mass (in grams) of the precipitate formed. Assume the reaction goes to completion. Do NOT include units in your answer. If you round during your calculation, be sure to keep at least three (3) decimal places. Report your answer to one (1) decimal place.