In a large city, a transportation engineer wants to estimate

Last updated: 7/29/2022

In a large city, a transportation engineer wants to estimate the proportion of residents who use the bus system regularly. Out of a random sample of 2000 residents, 1220 use the bus regularly. Construct and interpret the 99% confidence interval. (P-hat) = 1220 / 2000 = .61 (Q-hat) 1-.61 = .39 Standard Error = .010906 with a Z score of 2.5758 for the 99% confidence interval. .61 +2.5758 (.010906) = .6380 .612.5758 (.010906) = .5819 (.5819, .6380) So with a confidence interval of 99%, the true proportion of residents who use the bus system regularly is between 58.19% and 63.8%