In the Reaction: CuCl2 + 2 NaNO3 → Cu(NO3)2 + 2 NaCl If 17.2

Last updated: 7/23/2022

In the Reaction: CuCl2 + 2 NaNO3 → Cu(NO3)2 + 2 NaCl If 17.2 grams of copper (II) chloride, CuCl2, reacts with 22.6 grams of sodium nitrate, NaNO3, how many grams of sodium chloride, NaCl, will be produced? (4 points) Molar mass of CuCl2 = 134.45 g/mol Molar mass of NaNO3 = 85.00 g/mol Molar mass of NaCl = 58.44 g/mol Answers: 17.2 grams CuCl2 = 22.6 grams NaNO3 = g NaCl g NaCl What is the Limiting Reactant?