Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)₂(aq) +

Question

Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction
Pb(NO3)₂(aq) + 2NH4I(aq) → Pbl₂ (s) + 2NH4NO3(aq)
What volume of a 0.470 M NH4l solution is required to react with 239 mL of a 0.700 M Pb(NO3)2 solution?
How many moles of Pbl2 are formed from this reaction?

Kunduz · Accepted Answer

Click to see the answer