Let θ = arccos(-√3/2), then A) θ = 5π/6 and cos θ = -(√3/2)

Last updated: 8/4/2022

Let θ = arccos(-√3/2), then A) θ = 5π/6 and cos θ = -(√3/2) B) θ = -(7π/6) and cos θ = -(√3/2) C) θ = 7π/6 and cos θ = -(√3/2) D) θ = -5π/6 and cos θ = -(√3/2)