Let f(x) = x^3 + 3x^2 – 1. Calculate the derivative f'(x) =

Last updated: 8/11/2022

Let f(x) = x^3 + 3x^2 – 1. Calculate the derivative f'(x) = 3x^2 + 63 Calculate the second derivative f''(x) = 6x + 6 Note intervals are entered in the format (-00,5)U(7,00) (these are two infinite intervals). On what interval(s) is f increasing? Increasing: On what interval(s) is f decreasing? Decreasing: On what interval(s) is f concave downward? Concave Down: On what interval(s) is f concave upward? Concave Up: What is the limit as x approaches infinity? Limit is: What is the limit as x approaches negative infinity? Limit is: Sketch the graph and submit with your work.