Question:
non dominant hands of nine students Student ID 1 2 8 9 3 4 5
Last updated: 9/12/2023
non dominant hands of nine students Student ID 1 2 8 9 3 4 5 6 7 Dominant 28 0 28 5 29 8 31 0 31 3 32 5 34 1 34 6 Non dominant 21 0 26 2 29 6 27 0 22 5 27 1 29 5 29 7 31 0 34 6 Problem 1 Calculate the standard deviation and standard error for both the dominant and non dominant hand Step 1 Subtract each data value from the mean of the sample set This equals the deviation value Step 2 Square each of the deviation values Step 3 Sum the deviations 2 d Sample 1 data value mean deviation Sample 2 data value mean deviation