The following successive ionization energies correspond to an element in the third row of the periodic table: I1 = 786.3 kJ/mol,

Question

The following successive ionization energies correspond to an element in the third row of the periodic table:
I1 = 786.3 kJ/mol,
I2=1,580 kJ/mol,
I3= 3,230 kJ/mol,
I4=4,360 kJ/mol,
I5 = 16,000 kJ/mol, and
I6=20,000 kJ/mol.
Based on this pattern of ionization energies, identify the element.
A. Mg
B. Al
C. Si
D. P

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