Question:

Using y(t) = 110ekt, and the fact that y(30)= 75, we can

Last updated: 7/24/2022

Using y(t) = 110ekt, and the fact that y(30)= 75, we can

Using y(t) = 110ekt, and the fact that y(30)= 75, we can solve for k. y(t) = 110ekt y(30) =110ek. =110ek Thus, we have the following equation. k =