We are given that the perimeter of the rectangle is 88 m

Last updated: 7/15/2023

We are given that the perimeter of the rectangle is 88 m Therefore P 88 We substitute this value into the perimeter equation determined in the previous step P 21 2w 88 2 2w We then solve the resulting equation for I 88 2 2w 1 Next we substitute this expression for into the area equation determined in the previous step and expand the result A lw A w Recalling that area must be greater 0 we note that this equation is valid when 0 W