What is the mass of potassium sulfate in 500 mL of a 1.25 M potassium sulfate solution? We know the volume (500 mL or 0.5 L) and

Question

What is the mass of potassium sulfate in 500 mL of a 1.25 M potassium sulfate solution?
We know the volume (500 mL or 0.5 L) and we know the moles per liter, 1.25 M, but we need mass.
Solution:
• First, determine how many moles we have in solution:
125 x 0.500 L = 0.625 mol
• Then, convert that amount to grams. To do this you must get the molar mass of K,SO, from the periodic table 174,3 g/mol. Use the number of moles you calculated above to find grams of potassium sulfate
W
0.625 mol x
1743 g K, SO,
mal K, 50,
= 109 g K₂ SO4
Therefore, the mass of the K₂SO, that dissolves in 500 mL of H₂O to make this solution is 109 g.
Solve this problem on paper, then submit your answer to see the solution: How many grams of Ca (OH), are needed to make 100.0 mL of 0.250 M solution?

Kunduz · Accepted Answer

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