Question:

What mass of aluminum chloride is required to produce 0.125

Last updated: 7/31/2022

What mass of aluminum chloride is required to produce 0.125

What mass of aluminum chloride is required to produce 0.125 moles of aluminum sulfide according to the following equation? AlCl3 = 133.34 g/mol 2AICI3(aq) + 3H₂S(aq) → Al₂S3(s) + 6HCl(aq) 16.7 g 66.6 g 18.8 g 33.3 g