When 3.89 g of bismuth oxide (molar mass=465.96 g/ml) reacts with excess carbon to form 2.83 g of bismuth metal (molar

Question

When 3.89 g of bismuth oxide (molar mass=465.96 g/ml) reacts with excess carbon to form 2.83 g of bismuth metal (molar mass=208.98 g/mol) according to the equation:
Bi2O3(s) + 3 C(s)- 2 Bi(s) + 3 CO(g)
What is the percent yield of the reaction?

Kunduz · Accepted Answer

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