Probability Questions and Answers

If 6ft stands for a human height of at least 6 feet then P 6ft man is the probability O of being a man but not one who is 6ft tall O of being 6ft tall if the person is a man O of being a man and being 6ft tall O of being 6ft tall but not a man of being a man if the person is 6ft tall O of being neither a man nor 6ft tall
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If 6ft stands for a human height of at least 6 feet then P 6ft man is the probability O of being a man but not one who is 6ft tall O of being 6ft tall if the person is a man O of being a man and being 6ft tall O of being 6ft tall but not a man of being a man if the person is 6ft tall O of being neither a man nor 6ft tall
The probability of the entire sample space O can be any strictly positive value O is always equal to 1 O is usually a value smaller than 1 but always greater than 0 O can be any positive value
Statistics
Probability
The probability of the entire sample space O can be any strictly positive value O is always equal to 1 O is usually a value smaller than 1 but always greater than 0 O can be any positive value
Question 1 Which of the following was offered as an example of discrete sample space O zip codes O blood types O cholesterol levels amazon ratings
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Question 1 Which of the following was offered as an example of discrete sample space O zip codes O blood types O cholesterol levels amazon ratings
The following data represent the number of oranges in hundreds which were sold by various grocery stores in the month of June Construct a dot plot for the given data Answer 9 2 7 15 2 4 10 6 7 4 13 7 8 10 6 15 Copy Data Tables Keypad Keyboard Shortcuts Select any value to see the controls for increasing or decreasing the frequency Use the up and down arrows or drag the slider to change the number of dots
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The following data represent the number of oranges in hundreds which were sold by various grocery stores in the month of June Construct a dot plot for the given data Answer 9 2 7 15 2 4 10 6 7 4 13 7 8 10 6 15 Copy Data Tables Keypad Keyboard Shortcuts Select any value to see the controls for increasing or decreasing the frequency Use the up and down arrows or drag the slider to change the number of dots
1 B Book Street Books sells about 1290 books each month The circle graph displays the most popular book categories by percentage ach month science fiction 12 Categories of Books Sold romance 47 4 mystery 13 sports 12 computer 15 6 tep 1 of 5 Find the number of romance books sold each month Round your answer to the nearest integer
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1 B Book Street Books sells about 1290 books each month The circle graph displays the most popular book categories by percentage ach month science fiction 12 Categories of Books Sold romance 47 4 mystery 13 sports 12 computer 15 6 tep 1 of 5 Find the number of romance books sold each month Round your answer to the nearest integer
oh shows the per capita personal incomes for six states in 2003 Use this bar graph to answer the questions Income in Dollars 50 000 40 000 30 000 20 000 10 000 Per Capita Personal Income by State for 2003 29442 Georgia 25920 Montana 33749 California State 24977 Utah 48342 Dist of Columbia 29204 North Dakota
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oh shows the per capita personal incomes for six states in 2003 Use this bar graph to answer the questions Income in Dollars 50 000 40 000 30 000 20 000 10 000 Per Capita Personal Income by State for 2003 29442 Georgia 25920 Montana 33749 California State 24977 Utah 48342 Dist of Columbia 29204 North Dakota
21 B Book Street Books sells about 5200 books each month The pie chart displays the most popular book categories by percentage each month Find the number of science fiction books sold each month Round your answer to the nearest integer Reference 22 Categories of Books Sold Nonfiction 37 Children s Fiction 12 Science Fiction 9 Computer 20
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21 B Book Street Books sells about 5200 books each month The pie chart displays the most popular book categories by percentage each month Find the number of science fiction books sold each month Round your answer to the nearest integer Reference 22 Categories of Books Sold Nonfiction 37 Children s Fiction 12 Science Fiction 9 Computer 20
Jurisdiction Mediation Arbitration Summary Judgement Question 8 2 points Substantive law Saved specifies the steps to follow to enforce legal rights concerns equitable relief only creates defines and regulates rights and liabilities draws solely on English legal principles
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Jurisdiction Mediation Arbitration Summary Judgement Question 8 2 points Substantive law Saved specifies the steps to follow to enforce legal rights concerns equitable relief only creates defines and regulates rights and liabilities draws solely on English legal principles
1 B Book Street Books sells about 1800 books each month The pie chart displays the most popular book categories by percentage each month Find the number o omance books sold each month Round your answer to the nearest integer Children s Fiction 12 Categories of Books Sold Mystery 19 Romance 44 Science Fiction 15 Computer 10
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1 B Book Street Books sells about 1800 books each month The pie chart displays the most popular book categories by percentage each month Find the number o omance books sold each month Round your answer to the nearest integer Children s Fiction 12 Categories of Books Sold Mystery 19 Romance 44 Science Fiction 15 Computer 10
Service of process refers to a demand letter sent by the plaintiff to the defendant a reply sent to the plaintiff by the defendant O giving the defendant proper notice that a legal action is pending O a record of the court s preliminary hearing
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Service of process refers to a demand letter sent by the plaintiff to the defendant a reply sent to the plaintiff by the defendant O giving the defendant proper notice that a legal action is pending O a record of the court s preliminary hearing
ine the number of scores between 95 and 30 5 Scores on a Test Class Frequency 10 16 3 17 23 11 24 30 15 31 37 10 38 44 15
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ine the number of scores between 95 and 30 5 Scores on a Test Class Frequency 10 16 3 17 23 11 24 30 15 31 37 10 38 44 15
Scores on a Test Class Frequency 20 29 9 30 39 4 40 49 50 59 60 69 3 2 10
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Scores on a Test Class Frequency 20 29 9 30 39 4 40 49 50 59 60 69 3 2 10
A YouTube star knows that 56 of her viewers are under the age of 24 She wants to expand to other age groups so she updates her content to be more universal Then she collects a simple random survey of her her followers and finds that 36 of 67 of her viewers are still under the age of 24 Using a 5 significance level carIshe conclude that updating her content expanded her viewers age group
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Probability
A YouTube star knows that 56 of her viewers are under the age of 24 She wants to expand to other age groups so she updates her content to be more universal Then she collects a simple random survey of her her followers and finds that 36 of 67 of her viewers are still under the age of 24 Using a 5 significance level carIshe conclude that updating her content expanded her viewers age group
e following histogram shows the exam scores for a Prealgebra class Use this histogram to answer the questions Frequency 24 20 16 2 8 4 0 70 5 15 75 5 Prealgebra Exam Scores 20 80 5 11 85 5 Scores 90 5 9 95 5 4 100 5
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e following histogram shows the exam scores for a Prealgebra class Use this histogram to answer the questions Frequency 24 20 16 2 8 4 0 70 5 15 75 5 Prealgebra Exam Scores 20 80 5 11 85 5 Scores 90 5 9 95 5 4 100 5
120 100 80 60 40 20 0 Current weight pounds 220 180 Parrot tarsus length does not seem to be useful for predicting parrot weight given the form of the scatterplot 140 100 6 Current weight versus birth weight 12 year old boys r 0 19 60 0 Parrot weight versus tarsus length r 0 84 8 O 10 12 Tarsus mm 50 14 16 18 100 Birth weight oz 150 O 200 Birth weight does not appear to give useful information for predicting current weight for 12 year old boys according to the plot Answer Bank Stigma height mm 16 14 12 10 L Life expectancy years 80 60 40 O 0 Flower stigma height versus anther height r 0 79 0 12 Anther height mm For each percentage increase in anther height it is very likely that the stigma height increases by a proportional percentage O 10 20 8 80 Life expectancy versus age U S males r 0 99 40 O 60 Age years 14 OOOOOOOOOOOOOOOOOOOO 80 O 100 16 For each percentage increase in age it is very likely that the life expectancy increases by a proportional percentage 120
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120 100 80 60 40 20 0 Current weight pounds 220 180 Parrot tarsus length does not seem to be useful for predicting parrot weight given the form of the scatterplot 140 100 6 Current weight versus birth weight 12 year old boys r 0 19 60 0 Parrot weight versus tarsus length r 0 84 8 O 10 12 Tarsus mm 50 14 16 18 100 Birth weight oz 150 O 200 Birth weight does not appear to give useful information for predicting current weight for 12 year old boys according to the plot Answer Bank Stigma height mm 16 14 12 10 L Life expectancy years 80 60 40 O 0 Flower stigma height versus anther height r 0 79 0 12 Anther height mm For each percentage increase in anther height it is very likely that the stigma height increases by a proportional percentage O 10 20 8 80 Life expectancy versus age U S males r 0 99 40 O 60 Age years 14 OOOOOOOOOOOOOOOOOOOO 80 O 100 16 For each percentage increase in age it is very likely that the life expectancy increases by a proportional percentage 120
You roll two fair dice What is the probability that their sum is less than 11 O 1 36 O 35 36 3 36 O 33 36 O 5 36
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Probability
You roll two fair dice What is the probability that their sum is less than 11 O 1 36 O 35 36 3 36 O 33 36 O 5 36
O Macmillan Learning Match the appropriate boxplot to each histogram Frequency Height distribution US adults of age 18 20 200 150 100 50 6 2000 1500 1000 500 70 Height inches Birth weight distribution of U S children 0 250 200 100 150 Birth weight ounces Age distribution of the shot recipients U S adults in the Northeast over age 50 150 100 50 0 2000 1500 1000 500 60 0 Frequency 0585388 50 200 50 55 60 65 to 75 o Age years Time since quitting smoking U S adult former smokers 10 20 30 40 50 60 70 Duration years Age distribution of US women with hearing problems
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O Macmillan Learning Match the appropriate boxplot to each histogram Frequency Height distribution US adults of age 18 20 200 150 100 50 6 2000 1500 1000 500 70 Height inches Birth weight distribution of U S children 0 250 200 100 150 Birth weight ounces Age distribution of the shot recipients U S adults in the Northeast over age 50 150 100 50 0 2000 1500 1000 500 60 0 Frequency 0585388 50 200 50 55 60 65 to 75 o Age years Time since quitting smoking U S adult former smokers 10 20 30 40 50 60 70 Duration years Age distribution of US women with hearing problems
Select all of the true statements about the standard deviation of a quantitative variable Standard deviation is resistive to unusual values The standard deviation of a group of values is a measure of how far the values are from the mean Changing the units of a set of values e g converting from inches to feet does not affect its standard deviation Standard deviation is always a nonnegative value If a set of values has a mean of 0 and a standard deviation that is not 0 then adding a new data point with a value of 0 will have no effect on the standard deviation The standard deviation of a set of values is equal to 0 if and only if all of the values are the same
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Select all of the true statements about the standard deviation of a quantitative variable Standard deviation is resistive to unusual values The standard deviation of a group of values is a measure of how far the values are from the mean Changing the units of a set of values e g converting from inches to feet does not affect its standard deviation Standard deviation is always a nonnegative value If a set of values has a mean of 0 and a standard deviation that is not 0 then adding a new data point with a value of 0 will have no effect on the standard deviation The standard deviation of a set of values is equal to 0 if and only if all of the values are the same
Flextime scheduling is often offered to help recruit and keep women employees who have children at home Other workers sometimes view these flextime schedules as unfair An article indicates that male employees state that they have to pick up the slack for moms working flextime schedules A random sample is selected of 100 male employees working for companies offering flextime Complete through c Click here to view page 1 of the cumulative standardized normal distribution table Click here to view page 2 of the cumulative standardized normal distribution table a What is the probability that 33 or fewer male employees will indicate that they have to pick up the slack for moms working flextime P p 0 33 0 7437 Round to four decimal places as needed b What is the probability that 26 or fewer will indicate that they have to pick up the slack for moms working flextime P p 0 26 Round to four decimal places as needed Area under the cumulative standardized normal distribution from infinity to Z Z 6 0 5 5 5 0 4 5 0 00 0 000000001 0 000000019 0 000000287 0 000003398 4 0 0 000031671 3 9 0 00005 3 8 0 00007 3 7 0 00011 3 6 0 00016 3 5 0 00023 3 4 0 00034 3 3 0 00048 3 2 0 00069 3 1 0 00097 3 0 0 00135 2 9 0 0019 2 8 0 0026 2 7 0 0035 Cumulative Probabilities 0 01 0 02 0 03 0 04 0 05 0 06 0 07 0 08 0 09 0 000050 000040 000040 000040 000040 000040 000030 000030 00003 0 000070 000070 000060 000060 000060 000060 000050 000050 00005 0 000100 000 100 000 100 000090 000090 000080 000080 000080 00008 0 000150 000150 000140 000140 000130 000130 000120 000120 00011 0 000220 000220 000210 000200 000190 000190 000180 000170 00017 0 000320 000310 000300 000290 000280 000270 000260 000250 00024 0 000470 000450 000430 000420 000400 000390 000380 000360 00035 0 000660 000640 000620 000600 000580 000560 000540 000520 00050 0 000940 000900 000870 000840 000820 000790 000760 000740 00071 0 001310 001260 001220 001180 001140 00111 0 001070 001030 00100 0 0018 0 0018 0 0017 0 0016 0 0016 0 0015 0 0015 0 0014 0 0014 0 0025 0 0024 0 0023 0 0023 0 0022 0 0021 0 0021 0 0020 0 0019 0 0034 0 0033 0 0032 0 0031 0 0030 0 0029 0 0028 0 0027 0 0026
Statistics
Probability
Flextime scheduling is often offered to help recruit and keep women employees who have children at home Other workers sometimes view these flextime schedules as unfair An article indicates that male employees state that they have to pick up the slack for moms working flextime schedules A random sample is selected of 100 male employees working for companies offering flextime Complete through c Click here to view page 1 of the cumulative standardized normal distribution table Click here to view page 2 of the cumulative standardized normal distribution table a What is the probability that 33 or fewer male employees will indicate that they have to pick up the slack for moms working flextime P p 0 33 0 7437 Round to four decimal places as needed b What is the probability that 26 or fewer will indicate that they have to pick up the slack for moms working flextime P p 0 26 Round to four decimal places as needed Area under the cumulative standardized normal distribution from infinity to Z Z 6 0 5 5 5 0 4 5 0 00 0 000000001 0 000000019 0 000000287 0 000003398 4 0 0 000031671 3 9 0 00005 3 8 0 00007 3 7 0 00011 3 6 0 00016 3 5 0 00023 3 4 0 00034 3 3 0 00048 3 2 0 00069 3 1 0 00097 3 0 0 00135 2 9 0 0019 2 8 0 0026 2 7 0 0035 Cumulative Probabilities 0 01 0 02 0 03 0 04 0 05 0 06 0 07 0 08 0 09 0 000050 000040 000040 000040 000040 000040 000030 000030 00003 0 000070 000070 000060 000060 000060 000060 000050 000050 00005 0 000100 000 100 000 100 000090 000090 000080 000080 000080 00008 0 000150 000150 000140 000140 000130 000130 000120 000120 00011 0 000220 000220 000210 000200 000190 000190 000180 000170 00017 0 000320 000310 000300 000290 000280 000270 000260 000250 00024 0 000470 000450 000430 000420 000400 000390 000380 000360 00035 0 000660 000640 000620 000600 000580 000560 000540 000520 00050 0 000940 000900 000870 000840 000820 000790 000760 000740 00071 0 001310 001260 001220 001180 001140 00111 0 001070 001030 00100 0 0018 0 0018 0 0017 0 0016 0 0016 0 0015 0 0015 0 0014 0 0014 0 0025 0 0024 0 0023 0 0023 0 0022 0 0021 0 0021 0 0020 0 0019 0 0034 0 0033 0 0032 0 0031 0 0030 0 0029 0 0028 0 0027 0 0026
Anteny 153 3 159 3 239 7 243 6 329 4 395 8 395 8 411 5 421 5 454 5 461 12 10 8 6 173 184 3 206 8 235 5 349 4 392 2 392 8 400 1 404 9 408 4 429 1 464 5 431 5 440 5 466 4 470 6 472 6 476 6 479 5 480 5 487 2 491 9 507 7 522 6 523 8 530 5 530 5 530 5 619 6 541 2 565 621 5 630 3 582 4 582 6 594 9 634 8 635 635 9 651 7 4 2 395 8 427 4 464 5 15000258005000500056065000 length cm Find the first quartile for this data set Q Find the third quartile for this data set a Find the interquartile range for this data set IQR Find the lower fence separating outliers from usual values Fence Low Find the upper fence separating outliers from usual values
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Probability
Anteny 153 3 159 3 239 7 243 6 329 4 395 8 395 8 411 5 421 5 454 5 461 12 10 8 6 173 184 3 206 8 235 5 349 4 392 2 392 8 400 1 404 9 408 4 429 1 464 5 431 5 440 5 466 4 470 6 472 6 476 6 479 5 480 5 487 2 491 9 507 7 522 6 523 8 530 5 530 5 530 5 619 6 541 2 565 621 5 630 3 582 4 582 6 594 9 634 8 635 635 9 651 7 4 2 395 8 427 4 464 5 15000258005000500056065000 length cm Find the first quartile for this data set Q Find the third quartile for this data set a Find the interquartile range for this data set IQR Find the lower fence separating outliers from usual values Fence Low Find the upper fence separating outliers from usual values
18hop list of 280 students categorizes each according to the area of study engineering liberal arts and sciences The diagram uses the relative area to express class percentage Compute the frequency of Liberal Arts in the list of students choose the most appropriate one O 77 O 149 O 54 O 72 O 280 Engineering 2 5 Liberal Arts 1 5 Sciences 1 8
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Probability
18hop list of 280 students categorizes each according to the area of study engineering liberal arts and sciences The diagram uses the relative area to express class percentage Compute the frequency of Liberal Arts in the list of students choose the most appropriate one O 77 O 149 O 54 O 72 O 280 Engineering 2 5 Liberal Arts 1 5 Sciences 1 8
K Given a standardized normal distribution with a mean of 0 and a standard deviation of 1 complete parts a through d Click here to view page 1 of the cumulative standardized normal distribution table Click here to view page 2 of the cumulative standardized normal distribution table D C a What is the probability that Z is less than 1 047 The probability that Z is less than 1 04 is 0 8508 Round to four decimal places as needed b What is the probability that Z is greater than 0 267 The probability that Z is greater than 0 20 is Round to four decimal places as needed A Cumulative standardized normal distribution table page 1 Z 0 00 0 04 0 05 0 08 0 09 0 06 0 07 0 01 0 02 0 03 3 0 0 0014 0 0013 0 0013 0 0012 0 0012 0 0011 0 0011 0 0011 0 0010 0 0010 2 9 0 0019 0 0018 0 0018 0 0017 0 0016 0 0016 0 0015 0 0015 0 0014 0 0014 2 8 0 0026 0 0025 0 0024 0 0023 0 0023 0 0022 0 0021 0 0021 0 0020 0 0019 2 7 0 0035 0 0034 0 0033 0 0032 0 0031 0 0030 0 0029 0 0028 0 0027 0 0026 2 6 0 0047 0 0045 0 0044 0 0043 0 0041 0 0040 0 0039 0 0038 0 0037 0 0036 2 5 0 0062 0 0060 0 0059 0 0057 0 0055 0 0054 0 0052 0 0051 0 0049 0 0048 2 4 0 0082 0 0080 0 0078 0 0075 0 0073 0 0071 0 0069 0 0068 0 0066 0 0064 2 3 0 0107 0 0104 0 0102 0 0099 0 0096 0 0094 0 0091 0 0089 0 0087 0 0084 2 2 0 0139 0 0136 0 0132 0 0129 0 0125 0 0122 0 0119 0 0116 0 0113 0 0110 2 1 0 0179 0 0174 0 0170 0 0166 0 0162 0 0158 0 0154 0 0150 0 0146 0 0143 2 0 0 0228 0 0222 0 0217 0 0212 0 0207 0 0202 0 0197 0 0192 0 0188 0 0183 1 9 0 0287 0 0281 0 0274 0 0268 0 0262 0 0256 0 0250 0 0244 0 0239 0 0233 1 8 0 0359 0 0351 0 0344 0 0336 0 0329 0 0322 0 0314 0 0307 0 0301 0 0294 1 7 0 0446 0 0436 0 0427 0 0418 0 0409 0 0401 0 0392 0 0384 0 0375 0 0367 1 6 0 0548 0 0537 0 0526 0 0516 0 0505 0 0495 0 0485 0 0475 0 0465 0 0455 1 5 0 0668 0 0055 0 0643 0 0030 0 0018 0 0606 0 0594 0 0582 0 0571 0 0559 1 4 0 0808 0 0793 0 0778 0 0764 0 0749 0 0735 0 0721 0 0708 0 0694 0 0681 1 3 0 0968 0 0951 0 0934 0 0918 0 0901 0 0885 0 0869 0 0853 0 0838 0 0823 1 2 0 1151 0 1131 0 1112 0 1093 0 1075 0 1056 0 1038 0 1020 0 1003 0 0985 1 1 0 1357 0 1335 0 1314 0 1292 0 1271 0 1251 0 1230 0 1210 0 1190 0 1170 1 0 0 1587 0 1562 0 1539 0 1515 0 1492 0 1469 0 1446 0 1423 0 1401 0 1379 0 9 0 1841 0 1814 0 1788 0 1762 0 1736 0 1711 0 1685 0 1660 0 1635 0 1611 0 8 0 2119 0 2090 0 2061 0 2033 0 2005 0 1977 0 1949 0 1922 0 1894 0 1867 0 7 0 2420 0 2388 0 2358 0 2327 0 2296 0 2266 0 2236 0 2200 0 2177 0 2148 0 6 0 2743 0 2709 0 2676 0 2643 0 2611 0 2578 0 2546 0 2514 0 2482 0 2451 0 5 0 3085 0 3050 0 3015 0 2981 0 2946 0 2912 0 2877 0 2843 0 2810 0 2776 0 4 0 3446 0 3409 0 3372 0 3336 0 3300 0 3264 0 3228 0 3192 0 3156 0 3121 0 3 0 3821 0 3783 0 3745 0 3707 0 3669 0 3632 0 3594 0 3557 0 3520 0 3483 0 2 0 4207 0 4168 0 4129 0 4090 0 4052 0 4013 0 3974 0 3936 0 3897 0 3859 443 0 4404 04364 0 4325 0 4286 0 4247
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Probability
K Given a standardized normal distribution with a mean of 0 and a standard deviation of 1 complete parts a through d Click here to view page 1 of the cumulative standardized normal distribution table Click here to view page 2 of the cumulative standardized normal distribution table D C a What is the probability that Z is less than 1 047 The probability that Z is less than 1 04 is 0 8508 Round to four decimal places as needed b What is the probability that Z is greater than 0 267 The probability that Z is greater than 0 20 is Round to four decimal places as needed A Cumulative standardized normal distribution table page 1 Z 0 00 0 04 0 05 0 08 0 09 0 06 0 07 0 01 0 02 0 03 3 0 0 0014 0 0013 0 0013 0 0012 0 0012 0 0011 0 0011 0 0011 0 0010 0 0010 2 9 0 0019 0 0018 0 0018 0 0017 0 0016 0 0016 0 0015 0 0015 0 0014 0 0014 2 8 0 0026 0 0025 0 0024 0 0023 0 0023 0 0022 0 0021 0 0021 0 0020 0 0019 2 7 0 0035 0 0034 0 0033 0 0032 0 0031 0 0030 0 0029 0 0028 0 0027 0 0026 2 6 0 0047 0 0045 0 0044 0 0043 0 0041 0 0040 0 0039 0 0038 0 0037 0 0036 2 5 0 0062 0 0060 0 0059 0 0057 0 0055 0 0054 0 0052 0 0051 0 0049 0 0048 2 4 0 0082 0 0080 0 0078 0 0075 0 0073 0 0071 0 0069 0 0068 0 0066 0 0064 2 3 0 0107 0 0104 0 0102 0 0099 0 0096 0 0094 0 0091 0 0089 0 0087 0 0084 2 2 0 0139 0 0136 0 0132 0 0129 0 0125 0 0122 0 0119 0 0116 0 0113 0 0110 2 1 0 0179 0 0174 0 0170 0 0166 0 0162 0 0158 0 0154 0 0150 0 0146 0 0143 2 0 0 0228 0 0222 0 0217 0 0212 0 0207 0 0202 0 0197 0 0192 0 0188 0 0183 1 9 0 0287 0 0281 0 0274 0 0268 0 0262 0 0256 0 0250 0 0244 0 0239 0 0233 1 8 0 0359 0 0351 0 0344 0 0336 0 0329 0 0322 0 0314 0 0307 0 0301 0 0294 1 7 0 0446 0 0436 0 0427 0 0418 0 0409 0 0401 0 0392 0 0384 0 0375 0 0367 1 6 0 0548 0 0537 0 0526 0 0516 0 0505 0 0495 0 0485 0 0475 0 0465 0 0455 1 5 0 0668 0 0055 0 0643 0 0030 0 0018 0 0606 0 0594 0 0582 0 0571 0 0559 1 4 0 0808 0 0793 0 0778 0 0764 0 0749 0 0735 0 0721 0 0708 0 0694 0 0681 1 3 0 0968 0 0951 0 0934 0 0918 0 0901 0 0885 0 0869 0 0853 0 0838 0 0823 1 2 0 1151 0 1131 0 1112 0 1093 0 1075 0 1056 0 1038 0 1020 0 1003 0 0985 1 1 0 1357 0 1335 0 1314 0 1292 0 1271 0 1251 0 1230 0 1210 0 1190 0 1170 1 0 0 1587 0 1562 0 1539 0 1515 0 1492 0 1469 0 1446 0 1423 0 1401 0 1379 0 9 0 1841 0 1814 0 1788 0 1762 0 1736 0 1711 0 1685 0 1660 0 1635 0 1611 0 8 0 2119 0 2090 0 2061 0 2033 0 2005 0 1977 0 1949 0 1922 0 1894 0 1867 0 7 0 2420 0 2388 0 2358 0 2327 0 2296 0 2266 0 2236 0 2200 0 2177 0 2148 0 6 0 2743 0 2709 0 2676 0 2643 0 2611 0 2578 0 2546 0 2514 0 2482 0 2451 0 5 0 3085 0 3050 0 3015 0 2981 0 2946 0 2912 0 2877 0 2843 0 2810 0 2776 0 4 0 3446 0 3409 0 3372 0 3336 0 3300 0 3264 0 3228 0 3192 0 3156 0 3121 0 3 0 3821 0 3783 0 3745 0 3707 0 3669 0 3632 0 3594 0 3557 0 3520 0 3483 0 2 0 4207 0 4168 0 4129 0 4090 0 4052 0 4013 0 3974 0 3936 0 3897 0 3859 443 0 4404 04364 0 4325 0 4286 0 4247
Part 1 of 4 O Points 0 of 1 country conducts a study on new cars within the first 90 days of use The cars have been categorized according to whether the car needs a warranty based repair yes or no and the car s orig reign Based on the data collected the probability that the new car needs warranty repair is 0 12 the probability that the car was manufactured by a domestic company is 0 54 and the probal ar needs a warranty repair and was manufactured by a domestic company is 0 061 Construct a contingency table to evaluate the probabilities of a warranty related repair Complete parts a t What is the probability that a new car selected at random needs a warranty repair Do not round GOLD
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Probability
Part 1 of 4 O Points 0 of 1 country conducts a study on new cars within the first 90 days of use The cars have been categorized according to whether the car needs a warranty based repair yes or no and the car s orig reign Based on the data collected the probability that the new car needs warranty repair is 0 12 the probability that the car was manufactured by a domestic company is 0 54 and the probal ar needs a warranty repair and was manufactured by a domestic company is 0 061 Construct a contingency table to evaluate the probabilities of a warranty related repair Complete parts a t What is the probability that a new car selected at random needs a warranty repair Do not round GOLD
O Macmillan Learning For the straight line defined by the points 3 53 and 5 87 determine the slope m and y intercept b Do not round the answers m b
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Probability
O Macmillan Learning For the straight line defined by the points 3 53 and 5 87 determine the slope m and y intercept b Do not round the answers m b
A certain line is defined by the equation 5x 8 2 What is the value of the slope m y What is the y intercept of the line b Which graph correctly represents the line O 3 axis 6 5 4 2 3 B 2 1 0 0 1 2 3 4 5 6 6 5 4 3 2 1 0 1 2 3 4 5 6 x axis 3 axis 2 O y axis 11 10 9 8 7 6 5 4 3 2 1 0 1 8 7 6 5 4 3 2 1 0 1 2 3 4
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Probability
A certain line is defined by the equation 5x 8 2 What is the value of the slope m y What is the y intercept of the line b Which graph correctly represents the line O 3 axis 6 5 4 2 3 B 2 1 0 0 1 2 3 4 5 6 6 5 4 3 2 1 0 1 2 3 4 5 6 x axis 3 axis 2 O y axis 11 10 9 8 7 6 5 4 3 2 1 0 1 8 7 6 5 4 3 2 1 0 1 2 3 4
Linear Functions Fit to Data LC The graph shows a scatter plot for a set of data 20 Money Earned 19 18 17 16 16 14 12 12 11 10 6 5 4 2 4 Money Saved Which of the following equations is the best model for a line of fit for the data Oy 1 34x 21 5 O 134x 21 5 9 10 11 12 13 14 15 16 17 18 19 20 09 0 75x 17
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Probability
Linear Functions Fit to Data LC The graph shows a scatter plot for a set of data 20 Money Earned 19 18 17 16 16 14 12 12 11 10 6 5 4 2 4 Money Saved Which of the following equations is the best model for a line of fit for the data Oy 1 34x 21 5 O 134x 21 5 9 10 11 12 13 14 15 16 17 18 19 20 09 0 75x 17
W Use the accompanying radiation levels in for 50 different cell phones Find the percentile corresponding kg W kg Click the icon to view the radiation levels W The percentile corresponding to 0 62 kg Round to the nearest whole number as needed point s possible is
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Probability
W Use the accompanying radiation levels in for 50 different cell phones Find the percentile corresponding kg W kg Click the icon to view the radiation levels W The percentile corresponding to 0 62 kg Round to the nearest whole number as needed point s possible is
A survey found that women s heights are normally distributed with mean 62 7 in and standard deviation 2 8 in The survey also found that men s heights are normally distributed with mean 69 9 in and standard deviation 3 6 in Most of the live characters employed at an amusement park have height requirements of a minimum of 56 in and a maximum of 63 in Complete parts a and b below CITS a Find the percentage of men meeting the height requirement What does the result suggest about the genders of the people who are employed as characters at the amusement park The percentage of men who meet the height requirement is Round to two decimal places as needed Since most men the height requirement it is likely that most of the characters are b If the height requirements are changed to exclude only the tallest 50 of men and the shortest 5 of men what are the new height requirements The new height requirements are a minimum of in and a maximum of Round to one decimal place as needed in
Statistics
Probability
A survey found that women s heights are normally distributed with mean 62 7 in and standard deviation 2 8 in The survey also found that men s heights are normally distributed with mean 69 9 in and standard deviation 3 6 in Most of the live characters employed at an amusement park have height requirements of a minimum of 56 in and a maximum of 63 in Complete parts a and b below CITS a Find the percentage of men meeting the height requirement What does the result suggest about the genders of the people who are employed as characters at the amusement park The percentage of men who meet the height requirement is Round to two decimal places as needed Since most men the height requirement it is likely that most of the characters are b If the height requirements are changed to exclude only the tallest 50 of men and the shortest 5 of men what are the new height requirements The new height requirements are a minimum of in and a maximum of Round to one decimal place as needed in
The accompanying data set lists full IQ scores for a random sample of subjects with medium lead levels in their blood and another random sample of subjects with high lead levels in their blood Use a 0 05 significance level to test the claim that IQ scores of subjects with medium lead levels vary more than IQ scores of subjects with high lead levels OA Ho 0 0 2 H 0 0 2 OC Ho 0 0 2 H 0 0 2 Identify the test statistic The test statistic is Round to two decimal places as needed dentify the P value The P value is Round to three decimal places as needed What is the conclusion for this hypothesis test Let sample 1 be the sample with the larger sample variance and let sample 2 be the sample with the smaller sample variance What are the null and alternative hypotheses Medium B High Ho 0 0 2 H 0 0 2 114 92 100 77 93 111 91 72 98 90 91 92 46 71 85 78 OD Ho o 0 2 H 0 0 2 89 80 80 79 94 75 88 82 104 93 88 85 88 75 83 NO Sc Ng 52 Sc
Statistics
Probability
The accompanying data set lists full IQ scores for a random sample of subjects with medium lead levels in their blood and another random sample of subjects with high lead levels in their blood Use a 0 05 significance level to test the claim that IQ scores of subjects with medium lead levels vary more than IQ scores of subjects with high lead levels OA Ho 0 0 2 H 0 0 2 OC Ho 0 0 2 H 0 0 2 Identify the test statistic The test statistic is Round to two decimal places as needed dentify the P value The P value is Round to three decimal places as needed What is the conclusion for this hypothesis test Let sample 1 be the sample with the larger sample variance and let sample 2 be the sample with the smaller sample variance What are the null and alternative hypotheses Medium B High Ho 0 0 2 H 0 0 2 114 92 100 77 93 111 91 72 98 90 91 92 46 71 85 78 OD Ho o 0 2 H 0 0 2 89 80 80 79 94 75 88 82 104 93 88 85 88 75 83 NO Sc Ng 52 Sc
In a study of pulse rates of men a simple random sample of 152 men results in a standard deviation of 10 8 beats p minute The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute If the range rule o thumb is applied to that normal range the result is a standard deviation of 10 beats per minute Use the sample resu with a 0 01 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute see the accompanying StatCrunch display for this test What do the results indicate about the effectiven of using the range rule of thumb with the normal range from 60 to 100 beats per minute for estimating o in this cas Assume that the simple random sample is selected from a normally distributed population Click the icon to view the StatCrunch display Let o denote population standard deviation of the pulse rates of men in beats per minute Identify the null and alternative hypotheses Ho o H 0 Type integers or decimals Do not round Identify the test statistic Round to two decimal places as needed Identify the P value Round to three decimal places as needed
Statistics
Probability
In a study of pulse rates of men a simple random sample of 152 men results in a standard deviation of 10 8 beats p minute The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute If the range rule o thumb is applied to that normal range the result is a standard deviation of 10 beats per minute Use the sample resu with a 0 01 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute see the accompanying StatCrunch display for this test What do the results indicate about the effectiven of using the range rule of thumb with the normal range from 60 to 100 beats per minute for estimating o in this cas Assume that the simple random sample is selected from a normally distributed population Click the icon to view the StatCrunch display Let o denote population standard deviation of the pulse rates of men in beats per minute Identify the null and alternative hypotheses Ho o H 0 Type integers or decimals Do not round Identify the test statistic Round to two decimal places as needed Identify the P value Round to three decimal places as needed
Suppose 213 subjects are treated with a drug that is used to treat pain and 52 of them developed nausea Use a 0 05 significance level to test the claim that more than 20 of users develop nausea Identify the null and alternative hypotheses for this test Choose the correct answer below OA Ho p 0 20 H p 0 20 O B Ho p 0 20 H p 0 20 OC Ho p 0 20 H p 0 20 OD Ho p 0 20 H p 0 20 dentify the test statistic for this hypothesis test The test statistic for this hypothesis test is Round to two decimal places as needed dentify the P value for this hypothesis test The P value for this hypothesis test is Round to three decimal places as needed lentify the conclusion for this hypothesis test A Fail to reiect Ho There is sufficient evidence to warrant support of the claim that more than 30 of upgra
Statistics
Probability
Suppose 213 subjects are treated with a drug that is used to treat pain and 52 of them developed nausea Use a 0 05 significance level to test the claim that more than 20 of users develop nausea Identify the null and alternative hypotheses for this test Choose the correct answer below OA Ho p 0 20 H p 0 20 O B Ho p 0 20 H p 0 20 OC Ho p 0 20 H p 0 20 OD Ho p 0 20 H p 0 20 dentify the test statistic for this hypothesis test The test statistic for this hypothesis test is Round to two decimal places as needed dentify the P value for this hypothesis test The P value for this hypothesis test is Round to three decimal places as needed lentify the conclusion for this hypothesis test A Fail to reiect Ho There is sufficient evidence to warrant support of the claim that more than 30 of upgra
A study was conducted to measure the effectiveness of hypnotism in reducing pain The measurements are centimeters on a pain scale before and after hypnosis Assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal Construct a 95 confidence interval for the mean of the before after differences Does hypnotism appear to be effective in reducing pain Before After 9 3 6 8 0 7 2 2 11 3 7 1 Construct a 95 confidence interval for the mean of the before after differences Hd Round to two decimal places as needed Hd Does hypnotism appear to be effective in reducing pain OA Yes because the confidence interval includes zero OB No because the confidence interval does not include and is entirely greater than zero OC Yes because the confidence interval does not include and is entirely greater than zero OD No because the confidence interval includes zero 8 4 8 9 6 5 8 1 6 9 6 8 2 8 3 2 2 3 2 6 n
Statistics
Probability
A study was conducted to measure the effectiveness of hypnotism in reducing pain The measurements are centimeters on a pain scale before and after hypnosis Assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal Construct a 95 confidence interval for the mean of the before after differences Does hypnotism appear to be effective in reducing pain Before After 9 3 6 8 0 7 2 2 11 3 7 1 Construct a 95 confidence interval for the mean of the before after differences Hd Round to two decimal places as needed Hd Does hypnotism appear to be effective in reducing pain OA Yes because the confidence interval includes zero OB No because the confidence interval does not include and is entirely greater than zero OC Yes because the confidence interval does not include and is entirely greater than zero OD No because the confidence interval includes zero 8 4 8 9 6 5 8 1 6 9 6 8 2 8 3 2 2 3 2 6 n
K Listed in the accompanying table are weights lb of samples of the conterits of cans of regular Coke and Diet Coke Assume that the two samples are independent simple random samples selected from normally distributed populations Do not assume that the population standard deviations are equal Complete parts a to c Click the icon to view the data table of can weights a Use a 0 10 significance level to test the claim that the contents of cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke What are the null and alternative hypotheses Assume that population 1 consists of regular Coke and population 2 consists of Diet Coke OA Ho H H H Hy H O C Ho H H2 H H H The test statistic is The P value is Round to two decimal places as needed Round to three decimal places as needed State the conclusion for the test OB Ho H H H H H b Construct the confidence interval appropriate for the hypothesis test in part a 0 41 4 0 Round to five decimal places as needed O D Ho H H2 H H H O A Reject the null hypothesis There is sufficient evidence to support the claim that cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke OB Fail to reject the null hypothesis There is not sufficient evidence to support the claim that cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke OC Reject the null hypothesis There is not sufficient evidence to support the claim that cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke OD Fail to reject the null hypothesis There is sufficient evidence to support the claim that cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke
Statistics
Probability
K Listed in the accompanying table are weights lb of samples of the conterits of cans of regular Coke and Diet Coke Assume that the two samples are independent simple random samples selected from normally distributed populations Do not assume that the population standard deviations are equal Complete parts a to c Click the icon to view the data table of can weights a Use a 0 10 significance level to test the claim that the contents of cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke What are the null and alternative hypotheses Assume that population 1 consists of regular Coke and population 2 consists of Diet Coke OA Ho H H H Hy H O C Ho H H2 H H H The test statistic is The P value is Round to two decimal places as needed Round to three decimal places as needed State the conclusion for the test OB Ho H H H H H b Construct the confidence interval appropriate for the hypothesis test in part a 0 41 4 0 Round to five decimal places as needed O D Ho H H2 H H H O A Reject the null hypothesis There is sufficient evidence to support the claim that cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke OB Fail to reject the null hypothesis There is not sufficient evidence to support the claim that cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke OC Reject the null hypothesis There is not sufficient evidence to support the claim that cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke OD Fail to reject the null hypothesis There is sufficient evidence to support the claim that cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke
K The Minitab output shown below was obtained by using paired data consisting of weights in lb of 27 cars and their highway fuel consumption amounts in mi gal Along with the paired sample data Minitab was also given a car weight of 4000 lb to be used for predicting the highway fuel consumption amount Use the information provided in the display to determine the value of the linear correlation coefficient Be careful to correctly identify the sign of the correlation coefficient Given that there are 27 pairs of data is there sufficient evidence to support a claim of linear correlation between the weights of cars and their highway fuel consumption amounts Click the icon to view the Minitab display The linear correlation coefficient is Round to three decimal places as needed Is there sufficient evidence to support a claim of linear correlation OYes O No Minitab output The regression equation is Highway 50 7 0 00581 Weight Predictor SE Coef Coef Constant 50 708 2 766 Weight 0 0058083 0 0007504 S 2 24952 R Sq 65 6 R Sq adj 62 7 Predicted Values for New Observations New Obs 1 Fit 27 475 SE Fit 0 462 T P 17 99 0 000 7 45 0 000 95 CI 26 458 28 492 Values of Predictors for New Observations New 95 Pl 22 885 32 065
Statistics
Probability
K The Minitab output shown below was obtained by using paired data consisting of weights in lb of 27 cars and their highway fuel consumption amounts in mi gal Along with the paired sample data Minitab was also given a car weight of 4000 lb to be used for predicting the highway fuel consumption amount Use the information provided in the display to determine the value of the linear correlation coefficient Be careful to correctly identify the sign of the correlation coefficient Given that there are 27 pairs of data is there sufficient evidence to support a claim of linear correlation between the weights of cars and their highway fuel consumption amounts Click the icon to view the Minitab display The linear correlation coefficient is Round to three decimal places as needed Is there sufficient evidence to support a claim of linear correlation OYes O No Minitab output The regression equation is Highway 50 7 0 00581 Weight Predictor SE Coef Coef Constant 50 708 2 766 Weight 0 0058083 0 0007504 S 2 24952 R Sq 65 6 R Sq adj 62 7 Predicted Values for New Observations New Obs 1 Fit 27 475 SE Fit 0 462 T P 17 99 0 000 7 45 0 000 95 CI 26 458 28 492 Values of Predictors for New Observations New 95 Pl 22 885 32 065
K The test statistic of z 0 86 is obtained when testing the claim that p 0 5 a Identify the hypothesis test as being two tailed left tailed or right tailed b Find the P value c Using a significance level of a 0 05 should we reject Ho or should we fail to reject Ho Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table a This is a right tailed test b P value 0 195 Round to three decimal places as needed c Choose the correct conclusion below A Fail to reject Ho There is sufficient evidence to support the claim that p 0 5 B Fail to reject Ho There is not sufficient evidence to support the claim that p 0 5 OC Reject Ho There is not sufficient evidence to support the claim that p 0 5 O D Reject Ho There is sufficient evidence to support the claim that p 0 5
Statistics
Probability
K The test statistic of z 0 86 is obtained when testing the claim that p 0 5 a Identify the hypothesis test as being two tailed left tailed or right tailed b Find the P value c Using a significance level of a 0 05 should we reject Ho or should we fail to reject Ho Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table a This is a right tailed test b P value 0 195 Round to three decimal places as needed c Choose the correct conclusion below A Fail to reject Ho There is sufficient evidence to support the claim that p 0 5 B Fail to reject Ho There is not sufficient evidence to support the claim that p 0 5 OC Reject Ho There is not sufficient evidence to support the claim that p 0 5 O D Reject Ho There is sufficient evidence to support the claim that p 0 5
ee randomly selected children are surveyed The ages of the children are 2 4 and 9 Assume that samples of 2 are randomly selected with replacement from the population of 2 4 and 9 Listed below are the nine different ples Complete parts a through d 2 2 2 4 2 9 4 2 4 4 4 9 9 2 9 4 9 9 D or the population find the proportion of even numbers proportion is und to three decimal places as needed
Statistics
Probability
ee randomly selected children are surveyed The ages of the children are 2 4 and 9 Assume that samples of 2 are randomly selected with replacement from the population of 2 4 and 9 Listed below are the nine different ples Complete parts a through d 2 2 2 4 2 9 4 2 4 4 4 9 9 2 9 4 9 9 D or the population find the proportion of even numbers proportion is und to three decimal places as needed
Assume that the Poisson distribution applies and that the mean number of hurricanes in a certain area is 5 9 per year a Find the probability that in a year there will be 4 hurricanes b In a 35 year period how many years are expected to have 4 hurricanes c How does the result from part b compare to a recent period of 35 years in which 4 years had 4 hurricanes Does the Poisson distribution work well here a The probability is 0 16 Round to three decimal places as needed b The expected number of years with 4 hurricanes is 5 6 Round to one decimal place as needed c The result from part b is close to the number of hurricanes in the recent period of 35 years so the Poisson distribution does appear to work well in the given situation
Statistics
Probability
Assume that the Poisson distribution applies and that the mean number of hurricanes in a certain area is 5 9 per year a Find the probability that in a year there will be 4 hurricanes b In a 35 year period how many years are expected to have 4 hurricanes c How does the result from part b compare to a recent period of 35 years in which 4 years had 4 hurricanes Does the Poisson distribution work well here a The probability is 0 16 Round to three decimal places as needed b The expected number of years with 4 hurricanes is 5 6 Round to one decimal place as needed c The result from part b is close to the number of hurricanes in the recent period of 35 years so the Poisson distribution does appear to work well in the given situation
K Find the indicated critical value 20 02 Click to view page 1 of the table Click to view page 2 of the table Z0 02 Round to two decimal places as needed
Statistics
Probability
K Find the indicated critical value 20 02 Click to view page 1 of the table Click to view page 2 of the table Z0 02 Round to two decimal places as needed
The accompanying table describes the random variable x the numbers of adults in groups of five who reported sleepwalking Complete parts a through d below Click the icon to view the table a Find the probability of getting exactly 4 sleepwalkers among 5 adults Type an integer or a decimal Do not round b Find the probability of getting 4 or more sleepwalkers among 5 adults Type an integer or a decimal Do not round c Which probability is relevant for determining whether 4 is a significantly high number of sleepwalkers among 5 adults the result from part a or OA Since the probability of getting 4 sleepwalkers is the result from part a this is the relevant probability OB Since the probability of getting 5 sleepwalkers is less likely than getting 4 sleepwalkers the result from part a is the relevant probability OC Since the probability of getting fewer than 4 sleepwalkers is the complement of the result from part b this is the relevant probability OD Since the probability of getting 4 or more sleepwalkers is the probability of the given or more extreme result the result from part b is the d Is 4 a significantly high number of 4 sleepwalkers among 5 adults Why or why not Use 0 05 as the threshold for a significant event OA Yes since the appropriate probability is greater than 0 05 it is a significantly high number B Yes since the appropriate probability is less than 0 05 it is a significantly high number OC No since the appropriate probability is greater than 0 05 it is not a significantly high number OD No since the appropriate probability is less than 0 05 it is not a significantly high number Probability Distribution f X Print X 0 1 2 3 4 5 P x 0 184 0 379 0 269 0 136 0 025 0 007 Done
Statistics
Probability
The accompanying table describes the random variable x the numbers of adults in groups of five who reported sleepwalking Complete parts a through d below Click the icon to view the table a Find the probability of getting exactly 4 sleepwalkers among 5 adults Type an integer or a decimal Do not round b Find the probability of getting 4 or more sleepwalkers among 5 adults Type an integer or a decimal Do not round c Which probability is relevant for determining whether 4 is a significantly high number of sleepwalkers among 5 adults the result from part a or OA Since the probability of getting 4 sleepwalkers is the result from part a this is the relevant probability OB Since the probability of getting 5 sleepwalkers is less likely than getting 4 sleepwalkers the result from part a is the relevant probability OC Since the probability of getting fewer than 4 sleepwalkers is the complement of the result from part b this is the relevant probability OD Since the probability of getting 4 or more sleepwalkers is the probability of the given or more extreme result the result from part b is the d Is 4 a significantly high number of 4 sleepwalkers among 5 adults Why or why not Use 0 05 as the threshold for a significant event OA Yes since the appropriate probability is greater than 0 05 it is a significantly high number B Yes since the appropriate probability is less than 0 05 it is a significantly high number OC No since the appropriate probability is greater than 0 05 it is not a significantly high number OD No since the appropriate probability is less than 0 05 it is not a significantly high number Probability Distribution f X Print X 0 1 2 3 4 5 P x 0 184 0 379 0 269 0 136 0 025 0 007 Done
Examine the normal quantile plot and determine whether it depicts sample data from a population with a normal distribution Does the normal quantile plot depict sample data from a population with a normal distribution OA No The points do not lie close to a straight line OB Yes The points are evenly distributed above and below the mean 0 OC No The points exhibit some systematic pattern that is not a straight line pattern D Yes The pattern of the points is reasonably close to a straight line 3 00 2 00 1 00 0 00 1 00 2 00 3 00 60 80 100 120
Statistics
Probability
Examine the normal quantile plot and determine whether it depicts sample data from a population with a normal distribution Does the normal quantile plot depict sample data from a population with a normal distribution OA No The points do not lie close to a straight line OB Yes The points are evenly distributed above and below the mean 0 OC No The points exhibit some systematic pattern that is not a straight line pattern D Yes The pattern of the points is reasonably close to a straight line 3 00 2 00 1 00 0 00 1 00 2 00 3 00 60 80 100 120
Based on a survey 32 of likely voters would be willing to vote by internet instead of the in person traditional method of voting For each of the following assume that 13 likely voters are randomly selected Complete parts a through c below a What is the probability that exactly 10 of those selected would do internet voting Round to five decimal places as needed b If 10 of the selected voters would do internet voting is 10 significantly high Why or why not Select the correct choice below and fill in the answer box within your choice Round to five decimal places as needed OA Yes because the probability of 10 or more is OB Yes because the probability of 10 or more is OC No because the probability of 10 or more is O D No because the probability of 10 or more is c Find the probability that at least one of the selected likely voters would do internet voting Round to three decimal places as needed which is low which is not low which is not low which is low
Statistics
Probability
Based on a survey 32 of likely voters would be willing to vote by internet instead of the in person traditional method of voting For each of the following assume that 13 likely voters are randomly selected Complete parts a through c below a What is the probability that exactly 10 of those selected would do internet voting Round to five decimal places as needed b If 10 of the selected voters would do internet voting is 10 significantly high Why or why not Select the correct choice below and fill in the answer box within your choice Round to five decimal places as needed OA Yes because the probability of 10 or more is OB Yes because the probability of 10 or more is OC No because the probability of 10 or more is O D No because the probability of 10 or more is c Find the probability that at least one of the selected likely voters would do internet voting Round to three decimal places as needed which is low which is not low which is not low which is low
In a recent year an author wrote 193 checks Use the Poisson distribution to find the probability that on a randomly selected day he wrote at least one check The probability is Round to three decimal places as needed
Statistics
Probability
In a recent year an author wrote 193 checks Use the Poisson distribution to find the probability that on a randomly selected day he wrote at least one check The probability is Round to three decimal places as needed
K A research center poll showed that 83 of people believe that it is morally wrong to not report all income on tax returns What is the probability that someone does not have this belief The probability that someone does not believe that it is morally wrong to not report all income on tax returns is Type an integer or a decimal
Statistics
Probability
K A research center poll showed that 83 of people believe that it is morally wrong to not report all income on tax returns What is the probability that someone does not have this belief The probability that someone does not believe that it is morally wrong to not report all income on tax returns is Type an integer or a decimal
Identify the type of sampling used random systematic convenience stratified or cluster sampling in the situation described below A woman is selected by a marketing company to participate in a paid focus group The company says that the woman was selected because she was randomly chosen from all adults Which type of sampling did the marketing company use Cluster sampling O Systematic sampling Convenience sampling Stratified sampling Random sampling C
Statistics
Probability
Identify the type of sampling used random systematic convenience stratified or cluster sampling in the situation described below A woman is selected by a marketing company to participate in a paid focus group The company says that the woman was selected because she was randomly chosen from all adults Which type of sampling did the marketing company use Cluster sampling O Systematic sampling Convenience sampling Stratified sampling Random sampling C
K Which of the following values cannot be probabilities 0 03 2 0 59 0 1 1 36 5 3 3 5 Select all the values that cannot be probabilities A 3 5 B 0 59 C 5 5 3 3 D 1 E 0 03 F 2 G 0 H 1 36
Statistics
Probability
K Which of the following values cannot be probabilities 0 03 2 0 59 0 1 1 36 5 3 3 5 Select all the values that cannot be probabilities A 3 5 B 0 59 C 5 5 3 3 D 1 E 0 03 F 2 G 0 H 1 36
The range is 4550 million Round to the nearest integer as needed The variance is 3207750 million dollars squared Round to the nearest integer as needed The standard deviation is 1791 million Round to the nearest integer as needed What do the results tell us about the population of all celebrities OA Because the statistics are calculated from the data the measures of variation are typical for all celebrities B Because the data are from celebrities with the highest net worths the measures of variation are not at all typical for all celebrities OC Because the data are from celebrities with the highest net worths the measures of variation are typical for all celebrities D Because the statistics are calculated from the data the measures of variation cannot tell us about other celebrities Based on the nature of the amounts what can be inferred about their precision Because all of the amounts end with it appears that they are rounded to the nearest so it would make sense to round the results to the nearest
Statistics
Probability
The range is 4550 million Round to the nearest integer as needed The variance is 3207750 million dollars squared Round to the nearest integer as needed The standard deviation is 1791 million Round to the nearest integer as needed What do the results tell us about the population of all celebrities OA Because the statistics are calculated from the data the measures of variation are typical for all celebrities B Because the data are from celebrities with the highest net worths the measures of variation are not at all typical for all celebrities OC Because the data are from celebrities with the highest net worths the measures of variation are typical for all celebrities D Because the statistics are calculated from the data the measures of variation cannot tell us about other celebrities Based on the nature of the amounts what can be inferred about their precision Because all of the amounts end with it appears that they are rounded to the nearest so it would make sense to round the results to the nearest
K Let A denote the event of placing a 1 straight bet on certain lottery and winning Suppose that for this particular lottery there are 4 860 different ways that you can select the four digits with repetition allowed in this lottery and only one of those four digit numbers will be the winner What is the value of P A What is the value of P A What is the value of P A P A Round to five decimal places as needed
Statistics
Probability
K Let A denote the event of placing a 1 straight bet on certain lottery and winning Suppose that for this particular lottery there are 4 860 different ways that you can select the four digits with repetition allowed in this lottery and only one of those four digit numbers will be the winner What is the value of P A What is the value of P A What is the value of P A P A Round to five decimal places as needed
K For a certain horse race the odds in favor of a certain horse finishing in second place are given as 69 to 31 Express the indicated degree of likelihood as a probability value between 0 and 1 inclusive The probability is Round to two decimal places as needed
Statistics
Probability
K For a certain horse race the odds in favor of a certain horse finishing in second place are given as 69 to 31 Express the indicated degree of likelihood as a probability value between 0 and 1 inclusive The probability is Round to two decimal places as needed
A leading magazine like Barron s reported at one time that the average number of weeks an individual is unemployed is 28 weeks Assume that for the population of all unemployed individuals the population mean length of unemployment is 28 weeks and that the population standard deviation is 3 5 weeks Suppose you would like to select a random sample of 98 unemployed individuals for a follow up study Find the probability that a single randomly selected value is greater than 27 5 P X 27 5 Enter your answers as numbers accurate to 4 decimal places Find the probability that a sample of size n 98 is randomly selected with a mean greater than 27 5 P M 27 5 Enter your answers as numbers accurate to 4 decimal places
Statistics
Probability
A leading magazine like Barron s reported at one time that the average number of weeks an individual is unemployed is 28 weeks Assume that for the population of all unemployed individuals the population mean length of unemployment is 28 weeks and that the population standard deviation is 3 5 weeks Suppose you would like to select a random sample of 98 unemployed individuals for a follow up study Find the probability that a single randomly selected value is greater than 27 5 P X 27 5 Enter your answers as numbers accurate to 4 decimal places Find the probability that a sample of size n 98 is randomly selected with a mean greater than 27 5 P M 27 5 Enter your answers as numbers accurate to 4 decimal places
7 What is the critical value leeded to construct a Confidence interval for a Population mean with a confidence il 90 and 20 with degrees of freedom 01 645 02 086 61715 716
Statistics
Probability
7 What is the critical value leeded to construct a Confidence interval for a Population mean with a confidence il 90 and 20 with degrees of freedom 01 645 02 086 61715 716