N₂O3(g) + 6H2(g) → 2 NH3(g) + 3 H₂O(g) 0.22 mol of N2O3

Last updated: 8/5/2022

N₂O3(g) + 6H2(g) → 2 NH3(g) + 3 H₂O(g) 0.22 mol of N2O3(g) react with 0.87 mol of H₂(g) According to the equation above, how many moles of NH3(g) will form? a.0.29 mol b.44 mol c.73 mol d. 1.1 mol