Question:

1 Se Se 2 Te Te 4 0 0 Given the two concentration of HCN K

Last updated: 7/4/2023

1 Se Se 2 Te Te 4 0 0 Given the two concentration of HCN K

1 Se Se 2 Te Te 4 0 0 Given the two concentration of HCN K 10 are 0 1 M and 0 001 M respectively What will be the ratio of degree of dissociation 1 I 2 0 1 3 0 003 4 0 01 64 1 Se Se 3 S S HCN K 10 0 1 M 0 001 M 1 I 3 0 003 2 Te Te 4 0 0 facut 13 factGA EI 2 0 1 4 0 01