Question:

10 ii lonic Equilibrium aqueous solution of acetic acid is

Last updated: 6/28/2023

10 ii lonic Equilibrium aqueous solution of acetic acid is

10 ii lonic Equilibrium aqueous solution of acetic acid is mixed with 500 ml of 0 2 M HCl at 25 C Ka acetic acid 2 105 Calculate the degree of dissociation of acetic acid in the resulting solution and pH of the solution If 6g of NaOH is added to the above solution determine the final pH SOLUTION 0 2 CH COOH Just after mixing 0 1M 2 0 2 HC Just after mixing 2 Note Equal volumes added t 0 conc CH3COOH CH3COO H 0 0 1 leq c ca 0 1M H From HCI CH3COO H K CH3COOH H Total H From CH COOH H From HCI and H Total pH 1 ca co 0 1 0 1 c ca c a will be small due to common ion effect K ax0 1 Ka 0 1 ca ca 0 1 c ca ca 2 10 4 Check 1 a 1 2 104 1 co 0 1 0 1x2x10 0 1 0 1 M ii 6 gm NaOH 6 40 1 0 15 gmeq 150 mmoles NaOH These will react with CH COOH as NaOH CH COOH CH COONa H O 50 100 50 Mmoles HC1 500x0 2 100 mmoles NaOH will first react with HCl and if there is a leftover then it will react with CH COOH Mmoles NaOH left 150 100 50 Formation of an acidic buffer Salt Acid pH pK log10 50 4 7 log10 50 VTotal 50 V Total 4 7