Question:
150. mL of 0.350 M HCI was mixed with 150. mL of 0.350 M
Last updated: 8/4/2022
![150. mL of 0.350 M HCI was mixed with 150. mL of 0.350 M](https://media.kunduz.com/media/sug-question/raw/56752729-1659643354.8574185.jpeg?h=512)
150. mL of 0.350 M HCI was mixed with 150. mL of 0.350 M NaOH in a calorimeter (of negligible heat capacity). The initial temperature of the HCI and NaOH solutions was the same, 23.25°C, and the final temperature of the mixed solution was 25.60°C. Calculate the heat of neutralization for the reaction: NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O) dsol = 1.00 g/mL; S.H.sol = 4.184 J/g °C