Question:
(1+tan x)/(1-tan X)=[1+(sinx/cosx)cosx]/[1-(sinx/cosx)cosx]
Last updated: 8/4/2022
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(1+tan x)/(1-tan X)=[1+(sinx/cosx)cosx]/[1-(sinx/cosx)cosx] a)True b)False
Last updated: 8/4/2022
(1+tan x)/(1-tan X)=[1+(sinx/cosx)cosx]/[1-(sinx/cosx)cosx] a)True b)False